Algorithm
Check if Strings Can be Made Equal With Operations I
Solution
class Solution:
def canBeEqual(self, s1: str, s2: str) -> bool:
# Extract and sort even-indexed characters
evens_s1 = sorted([s1[0], s1[2]])
evens_s2 = sorted([s2[0], s2[2]])
# Extract and sort odd-indexed characters
odds_s1 = sorted([s1[1], s1[3]])
odds_s2 = sorted([s2[1], s2[3]])
# Both groups must match perfectly
return evens_s1 == evens_s2 and odds_s1 == odds_s2Video GuideLeetcode Daily
Time Complexity
O(1)
Space Complexity
O(1)
