Algorithm
Check if Strings Can Be Made Equal With Operations II
Solution
class Solution:
def checkStrings(self, s1: str, s2: str) -> bool:
return Counter(s1[::2]) == Counter(s2[::2]) and Counter(
s1[1::2]
) == Counter(s2[1::2])Video GuideLeetcode Daily
Time Complexity
O(n)
Space Complexity
O(k)