Algorithm

Find Minimum in Rotated Sorted Array II

Solution
class Solution:
    def findMin(self, nums: List[int]) -> int:
        left, right = 0, len(nums) - 1
        
        while left < right:
            mid = left + (right - left) // 2
            
            if nums[mid] > nums[right]:
                left = mid + 1
            elif nums[mid] < nums[right]:
                right = mid
            else:
                right -= 1
                
        return nums[left]

Time Complexity

O(log N) average, O(N) worst

Space Complexity

O(1)
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