Algorithm
Jump Game IV
Solution
# when current layer exists
while curs:
nex = []
# iterate the layer
for node in curs:
# check if reached end
if node == n-1:
return step
# check same value
for child in graph[arr[node]]:
if child not in visited:
visited.add(child)
nex.append(child)
# clear the list to prevent redundant search
graph[arr[node]].clear()
# check neighbors
for child in [node-1, node+1]:
if 0 <= child < n and child not in visited:
visited.add(child)
nex.append(child)
curs = nex
step += 1
return -1Time Complexity
O(N)
Space Complexity
O(N)
