Algorithm
Search in Rotated Sorted Array
Solution
class Solution:
def search(self, nums: List[int], target: int) -> int:
left, right = 0, len(nums) - 1
while left <= right:
mid = (left + right) // 2
if nums[mid] == target:
return mid
# Check if left half is sorted
if nums[left] <= nums[mid]:
if nums[left] <= target < nums[mid]:
right = mid - 1
else:
left = mid + 1
# Otherwise, right half must be sorted
else:
if nums[mid] < target <= nums[right]:
left = mid + 1
else:
right = mid - 1
return -1Video GuideLeetcode Daily
Time Complexity
O(log n)
Space Complexity
O(1)
